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Friday, December 15, 2006


Given that the polynomial x3 + ax2 + bx + c leaves the same remainder when divided by x + 1 or x - 2, show that a + b = -3.

is it like this:

let f(x) = x3 + ax2 + bx + c
let x + 1 = 0
therefore, x = -1
sub in:
-1 = -1 + a - b + c

let x - 2 = 0
therefore x = 2
sub in:
2 = 8 + 4a + 2b + c

is this correct? then how you continue?

-1 + a - b + c = 8 + 4a + 2b + c
?

= equals 2 strokes, use the 3 strokes thingy
-1 + a - b + c =(three strokes) 8 + 4a + 2b + c
?

or use what?


6:08 PM